Solution:
Heat is being transferred between two fluids
Heat transfer (Q) = m c ∆T
m = Mass of fluid
c = Specific Heat
Heat difference of Hot Air = 90 - 20 = 700C
Heat difference of Cold Water = X - 15
Specific heat of air = 1.005 KJ/kg K
Specific heat of Water = 4.187 KJ/kg K
Heat transferred from Hot to Cold fluids = Heat absorbed from Cold to Hot fluid
m cw ∆T = m cA ∆T
cw ∆T = cA ∆T
4.187 x (X - 15) = 1.005 x 70
X = 31.80C
Discuss in Forum:
Loading comments...